64y^2+16y+1=0

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Solution for 64y^2+16y+1=0 equation: 



64y^2+16y+1=0

a = 64; b = 16; c = +1;
Δ = b2-4ac
Δ = 162-4·64·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-16}{128}=-1/8$

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